1200=-3p^2+60+528

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Solution for 1200=-3p^2+60+528 equation: 



1200=-3p^2+60+528

We move all terms to the left:

1200-(-3p^2+60+528)=0

We get rid of parentheses

3p^2-60-528+1200=0

We add all the numbers together, and all the variables

3p^2+612=0

a = 3; b = 0; c = +612;
Δ = b2-4ac
Δ = 02-4·3·612
Δ = -7344
Delta is less than zero, so there is no solution for the equation

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